Ratio, proportion and compound measures
Proportional reasoning runs through the whole specification: recipes, currency, speed, density, growth and scale drawings are all the same idea in different clothing.
Lesson overview
What you'll learn in this lesson
Use proportional reasoning, probability and statistics to interpret and solve problems.
Key learning points
- • Ratio problems
- • Direct and inverse proportion
- • Compound measures and growth
This lesson at a glance
- 30 minutes
- 15 parts to scroll through
- 4 quick checks
- Marked quiz at the end
- Gentle pace: short sittings with pauses
Words to know
Scroll down — the lesson carries on below
Watch & discover
Part 1 of 15
Watch first
Ratio, proportion and compound measures
An English teaching video on this topic from mathantics. Watch it, then scroll down for the lesson.
In a nutshell
Use proportional reasoning, probability and statistics to interpret and solve problems.
Learning cycle
Part 2 of 15
Learning cycle 1 of 2
Part 1 · Ratio problems
A short piece of teaching, then a check to make sure it has landed.
Explore the idea
Part 3 of 15
Learn
Ratio problems
For sharing, add the parts, divide the total by that number and multiply back. When a question gives the difference between shares rather than the total, that difference corresponds to the difference in parts — a distinction that decides whether the answer is right.
Explore the idea
Part 4 of 15
Learn
Direct and inverse proportion
In direct proportion y = kx, so doubling x doubles y and the graph is a straight line through the origin. In inverse proportion y = k ÷ x, so doubling x halves y and the graph is a curve. Find k from the given pair, then use it for the unknown.
Quick check
Part 5 of 15
Quick check
£120 shared in the ratio 2 : 3 gives the larger share as
Quick check
Part 6 of 15
Quick check
In inverse proportion, doubling x
Reset break
Part 7 of 15
Pause
That's sitting 1 of 2 done
Stretch, get a drink, look out of the window. There is no timer and nothing is counting down — your place is saved, so you can come back in five minutes or tomorrow.
Learning cycle
Part 8 of 15
Learning cycle 2 of 2
Part 2 · Compound measures and growth
A short piece of teaching, then a check to make sure it has landed.
Explore the idea
Part 9 of 15
Learn
Compound measures and growth
Speed = distance ÷ time, density = mass ÷ volume, pressure = force ÷ area. For repeated percentage change, use a multiplier: a 4% annual rise over 3 years is × 1.04³. Reverse percentage questions divide by the multiplier, since the stated figure is the result, not the original.
Quick check
Part 10 of 15
Quick check
A 5% annual increase over 4 years uses the multiplier
Quick check
Part 11 of 15
Quick check
Density is
Explore the idea
Part 12 of 15
Worked example
Worked answer: after a 20% discount a coat costs £68. Find the original price (3 marks)
Paying 80% of the original gives a multiplier of 0.8 (1). The original price is therefore 68 ÷ 0.8 (1) = £85 (1). Adding 20% to £68 gives £81.60, which is wrong, because 20% of the larger original is more than 20% of the reduced price. Checking: 20% of £85 is £17, and £85 − £17 = £68.
Challenge round
Part 13 of 15
Game · Sort it
Which of these are true?
Drag each card into the right column. Tap a card first if dragging is fiddly.
True
Not true
Mastery quiz
Part 14 of 15
Marked quiz
End of lesson quiz: Ratio, proportion and compound measures
4 questions, marked with the reasoning shown. No timer.
1. £120 shared in the ratio 2 : 3 gives the larger share as
2. In inverse proportion, doubling x
3. A 5% annual increase over 4 years uses the multiplier
4. Density is
Lesson round-up
Part 15 of 15
Lesson round-up
Ready when you are
Quiz score
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Games
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Points this lesson
0
Best run
0 in a row
Luna: 0 out of 4 on the practice checks. Only if you feel up to it — one more?
Ask LunaDo the work
Your written work for this lesson
This is the part you'd do in your book at school. Pick the pieces below, write here or on paper, and photograph anything you draw or work out.
The cost of a school trip
A school is planning a trip to a wildlife park. The coach costs £480 however many people go. Entry costs £9.50 for each pupil and each adult goes free. The school says every pupil must pay the same amount, and the trip must not lose money.
If 60 pupils go, the coach works out at £8 each, so the total for each pupil is £17.50. If only 40 pupils go, the coach works out at £12 each, so the price rises to £21.50. The teacher explains that the coach is a fixed cost and the entry is a cost per person — which is why the price per pupil changes when the number changes.
The school decides to charge £20 and to use anything left over for a second trip later in the year.
Written for Good Learning Co.
Reading questions
- Work out the total cost of the trip if 50 pupils go.
- Show why the price per pupil falls when more pupils go, using numbers.
- At £20 each, how many pupils must go before the trip makes money? Show your working.
Working out
Working outDo the practice questions on paper, showing every step — not just the answer. Mark them yourself and circle anything you got wrong.
10–15 questions
Worked example, explained
WritingCopy one question out and write underneath, in words, why each step works.
1 question, 4–5 sentences
Problem in words
Working outWrite your own real-life problem that uses today's method, then solve it.
1 problem + solution
Saved as you type.
Part 1 of 15 · Watch & discover
