Chapter 5: Solving linear equations
An equation is a balance: every operation must preserve equality on both sides.
Part of your national curriculum
- Algebra: Use algebraic methods to solve linear equations in one variable, including all forms that require rearrangement
Lesson overview
What you'll learn in this lesson
Use algebraic methods to solve linear equations in one variable, including all forms that require rearrangement
Key learning points
- • Inverse operations
- • Unknowns on both sides
- • Check
This lesson at a glance
- 32 minutes
- 13 parts to scroll through
- 3 quick checks
- Marked quiz at the end
- Gentle pace: short sittings with pauses
Words to know
Scroll down — the lesson carries on below
Watch & discover
Part 1 of 13
Watch first
Chapter 5: Solving linear equations
An English teaching video on this topic from mathantics. Watch it, then scroll down for the lesson.
In a nutshell
Use algebraic methods to solve linear equations in one variable, including all forms that require rearrangement
Learning cycle
Part 2 of 13
Learning cycle 1 of 2
Part 1 · Inverse operations
A short piece of teaching, then a check to make sure it has landed.
Explore the idea
Part 3 of 13
Learn
Inverse operations
Solve 4x − 7 = 21 by adding 7 to both sides, then dividing both sides by 4. This gives x = 7.
Explore the idea
Part 4 of 13
Learn
Unknowns on both sides
For 5x + 2 = 2x + 20, subtract 2x from both sides, then subtract 2: 3x = 18, so x = 6.
Quick check
Part 5 of 13
Quick check
Solve 4x−7=21.
Reset break
Part 6 of 13
Pause
That's sitting 1 of 2 done
Stretch, get a drink, look out of the window. There is no timer and nothing is counting down — your place is saved, so you can come back in five minutes or tomorrow.
Quick check
Part 7 of 13
Quick check
Solve 5x+2=2x+20.
Learning cycle
Part 8 of 13
Learning cycle 2 of 2
Part 2 · Check
A short piece of teaching, then a check to make sure it has landed.
Explore the idea
Part 9 of 13
Learn
Check
Substitute the solution into the original equation. Both sides must produce the same number; if not, revisit each transformation.
Quick check
Part 10 of 13
Quick check
Why substitute the solution back?
Challenge round
Part 11 of 13
Game · Sort it
Which of these are true?
Drag each card into the right column. Tap a card first if dragging is fiddly.
True
Not true
Mastery quiz
Part 12 of 13
Marked quiz
End of lesson quiz: Chapter 5: Solving linear equations
3 questions, marked with the reasoning shown. No timer.
1. Solve 4x−7=21.
2. Solve 5x+2=2x+20.
3. Why substitute the solution back?
Lesson round-up
Part 13 of 13
Lesson round-up
Ready when you are
Quiz score
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Games
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Points this lesson
0
Best run
0 in a row
Luna: 0 out of 3 on the practice checks. Only if you feel up to it — one more?
Ask LunaDo the work
Your written work for this lesson
This is the part you'd do in your book at school. Pick the pieces below, write here or on paper, and photograph anything you draw or work out.
The cost of a school trip
A school is planning a trip to a wildlife park. The coach costs £480 however many people go. Entry costs £9.50 for each pupil and each adult goes free. The school says every pupil must pay the same amount, and the trip must not lose money.
If 60 pupils go, the coach works out at £8 each, so the total for each pupil is £17.50. If only 40 pupils go, the coach works out at £12 each, so the price rises to £21.50. The teacher explains that the coach is a fixed cost and the entry is a cost per person — which is why the price per pupil changes when the number changes.
The school decides to charge £20 and to use anything left over for a second trip later in the year.
Written for Good Learning Co.
Reading questions
- Work out the total cost of the trip if 50 pupils go.
- Show why the price per pupil falls when more pupils go, using numbers.
- At £20 each, how many pupils must go before the trip makes money? Show your working.
Working out
Working outDo the practice questions on paper, showing every step — not just the answer. Mark them yourself and circle anything you got wrong.
10–15 questions
Worked example, explained
WritingCopy one question out and write underneath, in words, why each step works.
1 question, 4–5 sentences
Problem in words
Working outWrite your own real-life problem that uses today's method, then solve it.
1 problem + solution
Saved as you type.
Part 1 of 13 · Watch & discover
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Use algebraic methods to solve linear equations in one variable, including all forms that require rearrangement
