Maths
MathsGCSE maths: algebra and graphs30 min★★★ difficulty

Linear, simultaneous and quadratic equations

Solving an equation means finding the values that make it true. The method changes with the type, but the principle — do the same to both sides — never does.

Lesson overview

What you'll learn in this lesson

Manipulate algebraic expressions, solve equations and interpret graphs of functions.

Key learning points

  • Linear equations and inequalities
  • Simultaneous equations
  • Quadratic equations

This lesson at a glance

  • 30 minutes
  • 20 parts to scroll through
  • 4 quick checks
  • Marked quiz at the end
  • Gentle pace: short sittings with pauses

Words to know

manipulatealgebraicexpressionsequationsinterpret

Scroll down — the lesson carries on below

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Part 1 of 20

Linear, simultaneous and quadratic equations illustrationVisual introduction

Picture this

Linear, simultaneous and quadratic equations

Solving an equation means finding the values that make it true. The method changes with the type, but the principle — do the same to both sides — never does.

In a nutshell

Manipulate algebraic expressions, solve equations and interpret graphs of functions.

2

Learning cycle

Part 2 of 20

Learning cycle 1 of 2

Part 1 · Linear equations and inequalities

A short piece of teaching, then a check to make sure it has landed.

3

Explore the idea

Part 3 of 20

Learn

Linear equations and inequalities

Collect terms and use inverse operations. Inequalities work identically with one exception: multiplying or dividing by a negative reverses the sign. Represent the solution on a number line with an open circle for < or > and a filled circle for ≤ or ≥.

4

Reset break

Part 4 of 20

Pause

That's sitting 1 of 5 done

Stretch, get a drink, look out of the window. There is no timer and nothing is counting down — your place is saved, so you can come back in five minutes or tomorrow.

Stop here for now
5

Explore the idea

Part 5 of 20

Learn

Simultaneous equations

Elimination: scale one or both equations so a variable has matching coefficients, then add or subtract. Substitution suits cases where one equation already gives a variable in terms of the other, and is essential when one equation is quadratic. Always substitute back to find the second variable and check both equations.

6

Quick check

Part 6 of 20

Quick check

Dividing an inequality by −2 means you must

7

Quick check

Part 7 of 20

Quick check

To solve x² − 5x + 6 = 0 by factorising, the brackets are

8

Reset break

Part 8 of 20

Pause

That's sitting 2 of 5 done

Stretch, get a drink, look out of the window. There is no timer and nothing is counting down — your place is saved, so you can come back in five minutes or tomorrow.

Stop here for now
9

Learning cycle

Part 9 of 20

Learning cycle 2 of 2

Part 2 · Quadratic equations

A short piece of teaching, then a check to make sure it has landed.

10

Explore the idea

Part 10 of 20

Learn

Quadratic equations

Rearrange to the form ax² + bx + c = 0 first. Factorise where possible, since a product equals zero only when a bracket equals zero. Otherwise use the quadratic formula or complete the square. A negative discriminant means there are no real solutions, which is itself a valid answer.

11

Quick check

Part 11 of 20

Quick check

A quadratic with a negative discriminant has

12

Reset break

Part 12 of 20

Pause

That's sitting 3 of 5 done

Stretch, get a drink, look out of the window. There is no timer and nothing is counting down — your place is saved, so you can come back in five minutes or tomorrow.

Stop here for now
13

Quick check

Part 13 of 20

Quick check

Before using the quadratic formula you must

14

Explore the idea

Part 14 of 20

Worked example

Worked answer: solve 3x + 2y = 16 and x − y = 2 (4 marks)

From the second equation, x = y + 2 (1). Substituting into the first: 3(y + 2) + 2y = 16, so 3y + 6 + 2y = 16 and 5y = 10 (1), giving y = 2 (1). Then x = 2 + 2 = 4 (1). Check in the first equation: 3(4) + 2(2) = 16, correct. Marks are lost most often by finding one variable and stopping.

15

Challenge round

Part 15 of 20

Game · Sort it

Which of these are true?

Drag each card into the right column. Tap a card first if dragging is fiddly.

True

Not true

16

Reset break

Part 16 of 20

Pause

That's sitting 4 of 5 done

Stretch, get a drink, look out of the window. There is no timer and nothing is counting down — your place is saved, so you can come back in five minutes or tomorrow.

Stop here for now
17

Challenge round

Part 17 of 20

Game · Fill the gaps

Finish the sentences

Choose the word that belongs in each gap.

Elimination: scale one or both ____ so a variable has matching coefficients, then add or subtract.

18

Challenge round

Part 18 of 20

Game · Recall cards

Dividing an inequality by −2 means you must

Card 1 of 4

19

Mastery quiz

Part 19 of 20

Marked quiz

End of lesson quiz: Linear, simultaneous and quadratic equations

4 questions, marked with the reasoning shown. No timer.

  1. 1. Dividing an inequality by −2 means you must

  2. 2. To solve x² − 5x + 6 = 0 by factorising, the brackets are

  3. 3. A quadratic with a negative discriminant has

  4. 4. Before using the quadratic formula you must

20

Lesson round-up

Part 20 of 20

Lesson round-up

Ready when you are

Quiz score

Not sat

Games

Not played

Points this lesson

0

Best run

0 in a row

Luna: 0 out of 4 on the practice checks. Only if you feel up to it — one more?

Ask Luna

Part 1 of 20 · Watch & discover

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