Expanding, factorising and algebraic proof
Algebraic manipulation is the grammar of GCSE maths. Fluent expanding and factorising unlocks equations, graphs, proof and most multi-step problems.
Lesson overview
What you'll learn in this lesson
Manipulate algebraic expressions, solve equations and interpret graphs of functions.
Key learning points
- • Expanding brackets
- • Factorising
- • Algebraic proof
This lesson at a glance
- 30 minutes
- 16 parts to scroll through
- 4 quick checks
- Marked quiz at the end
- Gentle pace: short sittings with pauses
Words to know
Scroll down — the lesson carries on below
Watch & discover
Part 1 of 16
Watch first
Expanding, factorising and algebraic proof
An English teaching video on this topic from Cognito. Watch it, then scroll down for the lesson.
In a nutshell
Manipulate algebraic expressions, solve equations and interpret graphs of functions.
Learning cycle
Part 2 of 16
Learning cycle 1 of 2
Part 1 · Expanding brackets
A short piece of teaching, then a check to make sure it has landed.
Explore the idea
Part 3 of 16
Learn
Expanding brackets
Multiply every term inside by every term outside. For double brackets, (x + 3)(x − 5) = x² − 5x + 3x − 15 = x² − 2x − 15. For triple brackets, expand two first, then multiply the result term by term, keeping the working in neat columns to avoid losing signs.
Explore the idea
Part 4 of 16
Learn
Factorising
Always look for a common factor first. For a quadratic x² + bx + c, find two numbers that multiply to c and add to b. Recognise the difference of two squares: x² − 49 = (x + 7)(x − 7). When the coefficient of x² is not 1, split the middle term and factorise in pairs.
Quick check
Part 5 of 16
Quick check
(x + 4)(x − 6) expands to
Quick check
Part 6 of 16
Quick check
x² − 81 factorises to
Reset break
Part 7 of 16
Pause
That's sitting 1 of 2 done
Stretch, get a drink, look out of the window. There is no timer and nothing is counting down — your place is saved, so you can come back in five minutes or tomorrow.
Learning cycle
Part 8 of 16
Learning cycle 2 of 2
Part 2 · Algebraic proof
A short piece of teaching, then a check to make sure it has landed.
Explore the idea
Part 9 of 16
Learn
Algebraic proof
Use algebra to represent the general case: 2n is any even number, 2n + 1 any odd number, and consecutive integers are n, n + 1, n + 2. Manipulate to a form that makes the conclusion unavoidable, then state it. Testing a few examples is verification, not proof, and scores nothing.
Quick check
Part 10 of 16
Quick check
Any odd number can be written as
Quick check
Part 11 of 16
Quick check
Factorising x² + 7x + 12 gives
Explore the idea
Part 12 of 16
Worked example
Worked answer: prove that the sum of three consecutive integers is always a multiple of 3 (3 marks)
Let the integers be n, n + 1 and n + 2, where n is any integer (1). Their sum is n + (n + 1) + (n + 2) = 3n + 3 (1). This factorises to 3(n + 1), which is 3 multiplied by an integer, so the sum is always a multiple of 3 (1). Showing that 4 + 5 + 6 = 15 would not be a proof.
Challenge round
Part 13 of 16
Game · Sort it
Which of these are true?
Drag each card into the right column. Tap a card first if dragging is fiddly.
True
Not true
Challenge round
Part 14 of 16
Game · Fill the gaps
Finish the sentences
Choose the word that belongs in each gap.
____ to a form that makes the conclusion unavoidable, then state it.
Mastery quiz
Part 15 of 16
Marked quiz
End of lesson quiz: Expanding, factorising and algebraic proof
4 questions, marked with the reasoning shown. No timer.
1. (x + 4)(x − 6) expands to
2. x² − 81 factorises to
3. Any odd number can be written as
4. Factorising x² + 7x + 12 gives
Lesson round-up
Part 16 of 16
Lesson round-up
Ready when you are
Quiz score
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Points this lesson
0
Best run
0 in a row
Luna: 0 out of 4 on the practice checks. Only if you feel up to it — one more?
Ask LunaDo the work
Your written work for this lesson
This is the part you'd do in your book at school. Pick the pieces below, write here or on paper, and photograph anything you draw or work out.
The cost of a school trip
A school is planning a trip to a wildlife park. The coach costs £480 however many people go. Entry costs £9.50 for each pupil and each adult goes free. The school says every pupil must pay the same amount, and the trip must not lose money.
If 60 pupils go, the coach works out at £8 each, so the total for each pupil is £17.50. If only 40 pupils go, the coach works out at £12 each, so the price rises to £21.50. The teacher explains that the coach is a fixed cost and the entry is a cost per person — which is why the price per pupil changes when the number changes.
The school decides to charge £20 and to use anything left over for a second trip later in the year.
Written for Good Learning Co.
Reading questions
- Work out the total cost of the trip if 50 pupils go.
- Show why the price per pupil falls when more pupils go, using numbers.
- At £20 each, how many pupils must go before the trip makes money? Show your working.
Working out
Working outDo the practice questions on paper, showing every step — not just the answer. Mark them yourself and circle anything you got wrong.
10–15 questions
Worked example, explained
WritingCopy one question out and write underneath, in words, why each step works.
1 question, 4–5 sentences
Problem in words
Working outWrite your own real-life problem that uses today's method, then solve it.
1 problem + solution
Saved as you type.
Part 1 of 16 · Watch & discover
