Prime factorisation, HCF and LCM
Every whole number greater than one is built from primes in exactly one way. That single fact is the tool behind HCF, LCM and simplifying surds.
Lesson overview
What you'll learn in this lesson
Apply number operations, accuracy and standard form to solve GCSE-style problems.
Key learning points
- • Writing a number as a product of primes
- • HCF and LCM from prime factors
- • Why examiners ask this
This lesson at a glance
- 30 minutes
- 15 parts to scroll through
- 4 quick checks
- Marked quiz at the end
- Gentle pace: short sittings with pauses
Words to know
Scroll down — the lesson carries on below
Watch & discover
Part 1 of 15
Watch first
Prime factorisation, HCF and LCM
An English teaching video on this topic from Cognito. Watch it, then scroll down for the lesson.
In a nutshell
Apply number operations, accuracy and standard form to solve GCSE-style problems.
Learning cycle
Part 2 of 15
Learning cycle 1 of 2
Part 1 · Writing a number as a product of primes
A short piece of teaching, then a check to make sure it has landed.
Explore the idea
Part 3 of 15
Learn
Writing a number as a product of primes
Divide repeatedly by the smallest prime that fits, then collect the factors using index notation: 360 = 2³ × 3² × 5. A factor tree and repeated division give the same result, and the answer is unique regardless of the route taken.
Explore the idea
Part 4 of 15
Learn
HCF and LCM from prime factors
The highest common factor is the product of the primes both numbers share, taking the lower index of each. The lowest common multiple takes every prime that appears, at the higher index. A Venn diagram makes this visible: the overlap gives HCF and the whole diagram gives LCM.
Quick check
Part 5 of 15
Quick check
360 as a product of primes is
Quick check
Part 6 of 15
Quick check
The HCF is found by taking shared primes at the
Reset break
Part 7 of 15
Pause
That's sitting 1 of 2 done
Stretch, get a drink, look out of the window. There is no timer and nothing is counting down — your place is saved, so you can come back in five minutes or tomorrow.
Learning cycle
Part 8 of 15
Learning cycle 2 of 2
Part 2 · Why examiners ask this
A short piece of teaching, then a check to make sure it has landed.
Explore the idea
Part 9 of 15
Learn
Why examiners ask this
HCF and LCM questions are usually dressed as contexts: two buses leaving together, tiles fitting a floor, ribbons cut into equal lengths. 'When do they coincide again' is an LCM question; 'largest equal size' is an HCF question. Naming which one you need is half the marks.
Quick check
Part 10 of 15
Quick check
Two buses leave every 12 and 18 minutes. They next leave together after
Quick check
Part 11 of 15
Quick check
The largest identical pieces from ribbons of 84 cm and 120 cm are
Explore the idea
Part 12 of 15
Worked example
Worked answer: find the HCF and LCM of 84 and 120 (4 marks)
84 = 2² × 3 × 7 and 120 = 2³ × 3 × 5 (1). HCF takes shared primes at the lower index: 2² × 3 = 12 (1). LCM takes every prime at the higher index: 2³ × 3 × 5 × 7 (1) = 840 (1). Checking: 84 × 120 = 10,080 = 12 × 840, which confirms both answers.
Challenge round
Part 13 of 15
Game · Sort it
Which of these are true?
Drag each card into the right column. Tap a card first if dragging is fiddly.
True
Not true
Mastery quiz
Part 14 of 15
Marked quiz
End of lesson quiz: Prime factorisation, HCF and LCM
4 questions, marked with the reasoning shown. No timer.
1. 360 as a product of primes is
2. The HCF is found by taking shared primes at the
3. Two buses leave every 12 and 18 minutes. They next leave together after
4. The largest identical pieces from ribbons of 84 cm and 120 cm are
Lesson round-up
Part 15 of 15
Lesson round-up
Ready when you are
Quiz score
Not sat
Games
Not played
Points this lesson
0
Best run
0 in a row
Luna: 0 out of 4 on the practice checks. Only if you feel up to it — one more?
Ask LunaDo the work
Your written work for this lesson
This is the part you'd do in your book at school. Pick the pieces below, write here or on paper, and photograph anything you draw or work out.
The cost of a school trip
A school is planning a trip to a wildlife park. The coach costs £480 however many people go. Entry costs £9.50 for each pupil and each adult goes free. The school says every pupil must pay the same amount, and the trip must not lose money.
If 60 pupils go, the coach works out at £8 each, so the total for each pupil is £17.50. If only 40 pupils go, the coach works out at £12 each, so the price rises to £21.50. The teacher explains that the coach is a fixed cost and the entry is a cost per person — which is why the price per pupil changes when the number changes.
The school decides to charge £20 and to use anything left over for a second trip later in the year.
Written for Good Learning Co.
Reading questions
- Work out the total cost of the trip if 50 pupils go.
- Show why the price per pupil falls when more pupils go, using numbers.
- At £20 each, how many pupils must go before the trip makes money? Show your working.
Working out
Working outDo the practice questions on paper, showing every step — not just the answer. Mark them yourself and circle anything you got wrong.
10–15 questions
Worked example, explained
WritingCopy one question out and write underneath, in words, why each step works.
1 question, 4–5 sentences
Problem in words
Working outWrite your own real-life problem that uses today's method, then solve it.
1 problem + solution
Saved as you type.
Part 1 of 15 · Watch & discover
